[NevoH72]

When using This HP Formula (((890+n)*n)^1.04)/2
How can I calculate the boss's HP for when 23 people are against him?
I want the boss to have around 22-23.5K HP in total when he's facing 23 (1v23) (He has 2 lives by the way.)

Is 890 enough? (Teach me please eitherway so I could set it to my liking)

P.S. That's my last thread before I finish the test boss, so thanks a lot!

[Batfoxkid]

n means amount of players, including the boss (except in 1.10.15 Beta).

Usually 890 is above average, average being (((760+n)*n)^1.04). So fit for tank based bosses or bosses that use above average HP.

For calculating the HP, replace n with amount of players + 1.

[NevoH72]

Originally Posted by Batfoxkid n means amount of players, including the boss (except in 1.10.15 Beta). Usually 890 is above average, average being (((760+n)*n)^1.04). So fit for tank based bosses or bosses that use above average HP. For calculating the HP, replace n with amount of players + 1.

Oh so that's why I was getting 16K+ when calculating... lmfao, I was so confused, because I've been told to put 890 for the boss to have 10.5K HP when 23 people are facing my boss. Thanks!

But the +1 counts me too? Like if 24 players in total are in the server, is it 25? or you're talking only about the opposing team to the boss +1 ?

[Batfoxkid]

Originally Posted by NevoH72 But the +1 counts me too? Like if 24 players in total are in the server, is it 25? or you're talking only about the opposing team to the boss +1 ?

Yes, the boss counts too when calculating. 1.10.15 Beta and some forks don't do this but common FF2 does.
Note it only counts once so companions are calculated, just itself.

[NevoH72]

So here's the question, does "(((720+24)*24)^1.04)/2"
sounds good for a boss with 2x lives? It's about 13.2K HP per life,should I reduce it?
(((760+24)*24)^1.04) sounds too much for a boss. It's 28K hp. ;o;

My idea was to let the boss have 11-13K hp per life with 23 people against him

[Batfoxkid]

Originally Posted by NevoH72 So here's the question, does "(((720+24)*24)^1.04)/2" sounds good for a boss with 2x lives? It's about 13.2K HP per life,should I reduce it? (((760+24)*24)^1.04) sounds too much for a boss. It's 28K hp. ;o; My idea was to let the boss have 11-13K hp per life with 23 people against him

What ever works with you.

[Maximilian_]

I was always curious, why such a complicated formula, if you can use like "y(x) = kx+b"

[Batfoxkid]

Originally Posted by Maximilian_ I was always curious, why such a complicated formula, if you can use like "y(x) = kx+b"

The complex formula helps with scaling player amount because for example,
3 players working together is more powerful while 3 players working independently isn't so much.

And the default formula is alot more complex: (((760.8+n)*(n-1))^1.0341)+2046

[NevoH72]

Originally Posted by Batfoxkid The complex formula helps with scaling player amount because for example, 3 players working together is more powerful while 3 players working independently isn't so much. And the default formula is alot more complex: (((760.8+n)*(n-1))^1.0341)+2046

oh btw, instead of making a new thread (lol) :

Do you know how I can add to my hale's model equipment on his back? Like how MLG Sniper's model has a sniper on his back.

[Batfoxkid]

Originally Posted by NevoH72 oh btw, instead of making a new thread (lol) : Do you know how I can add to my hale's model equipment on his back? Like how MLG Sniper's model has a sniper on his back.

That's probably a modeling thing, which I have no idea on modeling/rigging.