[Flipper_SPb]

How to remove from string all ^x, where x is digit from 0 to 8 ?

Example:

^1P^8layer^0 -> Player

[jim_yang]

\^[0-8] is the pattern
but amxx doesn't have regex_replace_all, and such simple case doesn't need to use regex.

void main()
{
	char a[] = "^1P^8layer^0";
	char b[100];
	int i = 0;
	int j = 0;
	char c;
	while(a[i])
	{
		if(a[i] == '^')
		{
			c = a[i + 1];
			if(c >= '0' && c <= '8')
			{
				i += 2;
				continue;
			}
		}
		b[j++] = a[i++];
	}
	b[j] = '\0';
	printf("%s\n", b);
	system("pause");
}

a C example.

[Flipper_SPb]

but amxx doesn't have regex_replace_all

Yes, I know

So, now I have:

PHP Code:

    replace_all(name, 31, "^^0", "")
    replace_all(name, 31, "^^1", "")
    replace_all(name, 31, "^^2", "")
    replace_all(name, 31, "^^3", "")
    replace_all(name, 31, "^^4", "")
    replace_all(name, 31, "^^5", "")
    replace_all(name, 31, "^^6", "")
    replace_all(name, 31, "^^7", "")
    replace_all(name, 31, "^^8", "") 


Is that a good solution in my case?

[jim_yang]

Don't you find any useful info from that example ? If so, sorry for wasting your time.

[Flipper_SPb]

jim_yang, thanks a lot! But I don't know which one is more effective.

[Arkshine]

It's not that hard to figure out. See the content of replace_all, see the content of his function. Now, when you see replace_all does much things by calling severals natives and you want to call it 9 times, vs the simple Jim's function called one time without calling natives ; it should be obvious, isn't it ?