[GsiX]

How do i get the different between my forward angle and the angle between me and my enemy?

[IMG]http://s8.************/uqu2nyuv9/Untitled.png[/IMG]

[Bimbo1]

#include <sourcemod>
#include <sdktools>
#include <cstrike>

#pragma semicolon 1

stock Float:getAngleBetweenPlayerForwardAndTarget(client, target){

	decl Float:ang[3];
	GetClientEyeAngles(client, ang);
	decl Float:vec[3];
	decl Float:targetPos[3];
	GetClientAbsOrigin(client, vec);
	GetClientAbsOrigin(target, targetPos);
	decl Float:fwd[3];
	new Float:sineA = Sine(ang[0]);
	fwd[0] = sineA*Cosine(ang[1]);
	fwd[1] = sineA*Sine(ang[1]);
	fwd[2] = Cosine(ang[0]);
	vec[0] = targetPos[0] - vec[0];
	vec[1] = targetPos[1] - vec[1];
	vec[2] = targetPos[2] - vec[2];
	ScaleVector(vec, 1.0/SquareRoot(vec[0]*vec[0]+vec[1]*vec[1]+vec[2]*vec[2]));
	return ArcCosine(vec[0]*fwd[0]+vec[1]*fwd[1]+vec[2]*fwd[2]);

}

ignore it —>

[Dr. Greg House]

Although I am pretty sure there is already a function for this, why care about the third component of the vectors? According to the diagram a 2d-approximation is sufficient.

[GsiX]

It always give me 1.6 in the different..
Maybe you forget "RadToDeg()". I need it in Degree. Million thanks man..

PHP Code:

stock Float:getAngleBetweenPlayerForwardAndTarget( subject, target )
{
    decl Float:ang[3];
    decl Float:vec[3];
    decl Float:targetPos[3];
    GetEntPropVector( subject, Prop_Data, "m_angRotation", ang );
    GetEntPropVector( subject, Prop_Send, "m_vecOrigin", vec );
    GetEntPropVector( target, Prop_Send, "m_vecOrigin", targetPos );
    
    decl Float:fwd[3];
    new Float:sineA = Sine(ang[0]);
    fwd[0] = sineA*Cosine(ang[1]);
    fwd[1] = sineA*Sine(ang[1]);
    fwd[2] = Cosine(ang[0]);
    vec[0] = targetPos[0] - vec[0];
    vec[1] = targetPos[1] - vec[1];
    vec[2] = targetPos[2] - vec[2];
    ScaleVector(vec, 1.0/SquareRoot(vec[0]*vec[0]+vec[1]*vec[1]+vec[2]*vec[2]));
    return ArcCosine(vec[0]*fwd[0]+vec[1]*fwd[1]+vec[2]*fwd[2]);
} 


EDIT:

Originally Posted by Dr. Greg House Although I am pretty sure there is already a function for this, why care about the third component of the vectors? According to the diagram a 2d-approximation is sufficient.

Woops.. didn't see your post..
Anyway, my math is very poor.. i dont know what you talking about..

[11530]

Originally Posted by GsiX Woops.. didn't see your post.. Anyway, my math is very poor.. i dont know what you talking about..

He's saying that the up/down component of the vector doesn't need to be looked at, since you're only concerned with the left/right angles. Looking up or down won't change your x angle.

[GsiX]

Originally Posted by 11530 He's saying that the up/down component of the vector doesn't need to be looked at, since you're only concerned with the left/right angles. Looking up or down won't change your x angle.

Yes.. that correct.. i only need left/right..
But i will appreciate if it always calculate in Counter Clock Wise (if by mean possible). Easy for me to do the next steps.

[Bimbo1]

there are functions for a lot of things, but i like to optmize things when i can. also, it's just a diagram, it's supposed to be simple. that doesn't exclude the possibility of he wanting it in 3d. well, it's not hard to make it 2d, though.
what do you mean by calculate in counter clock wise?

[GsiX]

Nvm.. i dont think its possible..
So may you get the calculation for me then..?

[Bimbo1]

what's not possible and calculate what?

[GsiX]

To calculate the angle result in CCW direction. I mean from 0 degree to 360 degree.. or at least 180 degree.

EDIT: I dont actually know how the degree work so if it cant happen just ignore it.. simply some degree number will fulfill my need..