how to create isStringFloat?

grs4 · **Author**

how to create a function that checks if string is exactly a float?

PHP Code:


			
stock bool:isStringFloat(szText[], len)
{
    trim(szText), num, line;

    if(containi(szText, ".") == -1)
        return false;
    
    for(new i = 0; i < len; i++)
    {
        line = szText[i];

        if(isdigit(line))
            continue;
        else if(line == '.')
        {
            if(num == 1)
                return false;
            num++;
            continue;
        }
        else
            return false;
    }
    return true;
}

Is code above a good code?

OciXCrom · 03-02-2017 , 09:20 Re: how to create isStringFloat?

PHP Code:


			
if(str_to_float(szText))

grs4 · 03-02-2017 , 09:23 Re: how to create isStringFloat?

or floatstr, yeah, i know, but i remember when i did like this, if i set a string with 'a' a float would be returned as '4124142.42312' or something like that. not '0'

klippy · 03-02-2017 , 09:24 Re: how to create isStringFloat?

Quote:

Originally Posted by OciXCrom

PHP Code:


			
if(str_to_float(szText))

But "0.0" is also a floating point value.

There's is_str_float() in String Stocks.

grs4 · 03-02-2017 , 09:25 Re: how to create isStringFloat?

PHP Code:


			
stock bool:is_str_float(const string[])
{
    new c, i, p;
    while(is_char(c = string[i++]))
    {
        if(!isdigit(c))
        {
            if(c != '.' || p)
            {
                return false;
            }
            
            p = 1;
        }
    }
    
    return (i > 1);
}

Oh, so just like my code. thanks

Natsheh · *Last edited by Natsheh; 03-03-2017 at 17:59.*

PHP Code:


			
stock bool:is_str_float(const sString[])
{
    new p = strlen(sString);
    if(p < 3) return false;
    
    for(new i = 0; i < p; i++)
    {
        if(!isdigit(sString[i]) && sString[i] != '.')
            return false;
    }
    
    new i = contain(sString, ".");
    if(i <= 0 || i == (p-1) || contain(sString[i+1],".") > -1) return false;
    
    return true;
}

TESTED AND WORKS CHARMING !!!

grs4 · *Last edited by grs4; 03-03-2017 at 16:16.*

on my eye

For your example

Code:

a5.5a

will return true

and also

Code:

.5

will throw an error. Index out of bounds.

i see you edited code.

Code:

5.5.

will not work

why? because "for" loop will pass by, but

PHP Code:


			
new i = Contain(sString, ".") // will return 0
If(i <= 0 /*false*/|| i == (p-1) /*false*/|| contain(sString[i+1],".") > -1 /*false, because i+1 = 5 */) return false;

</span></span>

Natsheh · *Last edited by Natsheh; 03-03-2017 at 16:35.*

Have you tested it?

Btw ik i+1 is equal to 5 but the contain native will ignore the previous '.' and start searching for a new one starting from that position which is (i+1 // 5), if it found an extra dot will return false remember contain native handles with a strings not a character

new i = Contain(sString, ".") // will return 0
And why this will return 0 if it based on this 5.5. The correct result will be 1

grs4 · *Last edited by grs4; 03-03-2017 at 16:54.*

I dont test it, because i'm not on pc with amxx

Code:

Btw ik i+1 is equal to 5 but the contain native will ignore the previous  '.' and start searching for a new one starting from that position which  is (i+1 // 5)

Quote:

return: -1 if failure. Any other value indicates a position in the string where the match starts.

If i understand you well, we can't set contain/i start postion for looking match text in PAWN.

Code:

contain(sString[i+1],".")

Will check if "5" contains "." which returns -1 ( false )

Natsheh · *Last edited by Natsheh; 03-04-2017 at 09:13.*

Quote:

Originally Posted by grs4

I dont test it, because i'm not on pc with amxx

Code:

Btw ik i+1 is equal to 5 but the contain native will ignore the previous  '.' and start searching for a new one starting from that position which  is (i+1 // 5)

If i understand you well, we can't set contain/i start postion for looking match text in PAWN.

Code:

contain(sString[i+1],".")

Will check if "5" contains "." which returns -1 ( false )

i just tested it and it works very good !

Will check if the string "5." contains "." which will returns 1