[Kapuzzino]

It returns me only the first number, instead of both

PHP Code:

new str[] = "that string contains 55 and 46 numbers"
new pattern[] = "(\d{2})"
new flags[] = "mis"
new num,err[128]
new str2
new Regex:re = regex_match(str,pattern,num,err,127,flags)
server_print("Result=%d Num=%d Error=%s",re,num,err)

if (re >= REGEX_OK)
{
    new str2[64]
    new i
    
   for (i=0; i<num; i++)
   {
    regex_substr(re,i,str2,63)
    server_print("Substring %d: %s", i, str2)
   }
}
          
regex_free(re) 


results:

Substring 0: 55
Substring 1: 55

[jimaway]

regex for amxx is pretty limited, as you can see, it doesn't have a global match flag. you have to use regex_match in a loop to check for more matches, while removing previous match from the string.

you get 55 twice probably cause your pattern is in parentheses

[Kapuzzino]

you get 55 twice probably cause your pattern is in parentheses

I think that is must be so, the first match is always must contain whole matches.

any example in a loop for that?

regex for amxx is pretty limited

Maybe it depends of other functions in regex lib, like regex_match_c or regex_compile?

[jimaway]

    new str[] = "that string 44 contains 55 and 46 numbers 88"
    new pattern[] = "\d\d"
    new flags[] = "mi"
    new num,err[128]
    new Regex:re
    new pos = 0

    while (strlen(str[pos]) > 0 && (re = regex_match(str[pos],pattern,num,err,127,flags))>= REGEX_OK )
    {
        new str2[64]
    
        regex_substr(re,0,str2,63)
        server_print("Substring: %s", str2)
        pos += contain(str[pos], str2) + strlen(str2)
    } 
          
    regex_free(re)

[Kapuzzino]

yes, thats working, I hope I'll found out how to parse whole html page as well.

p.s. if I get it.