[xbatista]

So how to get "||" in #if defined?
Example:

PHP Code:

#if defined XX || XX2 


Or maybe this?

PHP Code:

#if defined XX | XX2 


Which of this is true?

[fysiks]

In a C book I found:

#if defined VAR1 && defined VAR2

I would assume you could use "logical OR" also.

Just test it. If you get an error or incorrect result then it doesn't work.

[xbatista]

Error: extra characters online.

PHP Code:

#define XX
//#define XX2
#else if defined XX || defined XX2 


Maybe "else" bad?

[fysiks]

Why do you have and else in there?

look at my post again.

[xbatista]

I've just have a problem with "else" and I need "||"

PHP Code:

#if defined XX3
do_something(id)
#else if defined XX || defined XX2
do2_something(id)
#endif 


[Bugsy]

Use elseif not else if

[xbatista]

Use elseif not else if

Omg thx
And,
What i must use? "||" or this "|" ?

[Bugsy]

| = bit-wise OR
|| = conditional OR

Use ||

[fysiks]

use "||" (it's the logical operator) "|" is a bitwise operator I believe.

[xbatista]

WoW,thx for explaining. ;)
EDIT:
Something again wrong in this line:
#elseif defined XX || defined XX2