[Sp@jk]

so, I have a file called bla.ini and there is a line:

"1. arg" "2. arg" "3. arg"

so, I read that line, but how can I get 1. arg, 2. arg and 3. arg ?
so, I need to put "1. arg" to arg1[len], "2. arg" to arg2[len] and "3. arg" to arg3[len]

somebody understands ?

[nikhilgupta345]

PHP Code:

new szDirectory[ 256 ];
get_configsdir( szDirectory, charsmax( szDirectory ) );

add( szDirectory, charsmax( szDirectory ), "/config.ini" );

new iFile = fopen( szDirectory, "rt" );

new szBuffer[ 256 ], szArg1[ 32 ], szArg2[ 32 ], szArg3[ 32 ];

while( !feof( iFile ) )
{
    fgets( iFile, szBuffer, charsmax( szBuffer ) );
    
    parse( szBuffer, szArg1, charsmax( szArg1 ), szArg2, charsmax( szArg2 ), szArg3, charsmax( szArg3 ) );
    
    // szArg1 contains "1. arg"
    // szArg2 contains "2. arg"
    // szArg3 contains "3. arg"
} 


[Sp@jk]

I thinked that parse would "cut"

"1. arg" "2. arg" "3. arg"

to "1. arg" "2. arg" "3. arg"

[nikhilgupta345]

If you have quotes around sets of text, then parse will treat everything in that quote as one string.

So like I said, from the previous code

szArg1 would have "1. arg"
szArg2 would have "2. arg"
and szArg3 would have "3. arg"

[Sp@jk]

ok, thanks