Simple task dose not work. argument type mismatch(argument 1)

Hay · **Author**

Tried to print to chat player health, I had a few problems. argument type mismatch(argument 1)

Quote:

public Action:Command_health(client,args)
{
int y = GetClientHealth(client);
PrintToChatAll(y);
}

Some help?

MasterMind420

Quote:

Originally Posted by Hay

Tried to print to chat player health, I had a few problems. argument type mismatch(argument 1)

Some help?

Code:

public Action Command_health(int client, int args)
{
     int y = GetClientHealth(client);
     PrintToChatAll("%i", y);
}

This is converted completely to new syntax.
Also you formatted PrintToChatAll incorrectly.
You should take a look at the sourcemod API
It's a great reference. Also if in doubt google
search Allied Modders PrintToChatAll, good luck.

Hay · *Last edited by Hay; 06-08-2018 at 14:39.*

Quote:

Originally Posted by MasterMind420

Code:

public Action Command_health(int client, int args)
{
     int y = GetClientHealth(client);
     PrintToChatAll("%i", y);
}

This is converted completely to new syntax.
Also you formatted PrintToChatAll incorrectly.
You should take a look at the sourcemod API
It's a great reference. Also if in doubt google
search Allied Modders PrintToChatAll, good luck.

First thanks for the help, Sec I need to use it more than 1 time. and its give me the error: "Number of arguments does not a definition" I Looked out for it and didn't find .

pride95

Quote:

Originally Posted by Hay

First thanks for the help, Sec I need to use it more than 1 time. and its give me the error: "Number of arguments does not a definition" I Looked out for it and didn't find .

PHP Code:


			


int Client, Money;

char[100] String;



PrintToChatAll("%d %d %s", Client, Money, String);

3 parameters, 3 formats (%d, %d, %s)

%d or %i for int
%s for char vector (char[])
%c for char character (char)
%f for float
%N for client name

Hay · *Last edited by Hay; 06-08-2018 at 14:51.*

Quote:

Originally Posted by pride95

PHP Code:


			

int Client, Money;
char[100] String;

PrintToChatAll("%d %d %s", Client, Money, String);

3 parameters, 3 formats (%d, %d, %s)

%d or %i for int
%s for char vector (char[])
%c for char character (char)
%f for float
%N for client name

tnx again, but what the problem with this code? -

Quote:

public Action:Command_health(client,args)
{
int health = GetClientHealth(client);
int name = GetClientName(client);
PrintToChatAll("%N","%i",name, health);
}

Error - "Number of arguments does not definition"

MasterMind420 · *Last edited by MasterMind420; 06-08-2018 at 15:00.*

Change "%N","%i" to just "%N %i"...anything printed goes within a single parenthesis.

PrintToChatAll("%d %d %s", Client, Money, String); Like pride95's example

Hay

Quote:

Originally Posted by MasterMind420

Change "%N","%i" to just "%N %i"...anything printed goes within a single parenthesis.

PrintToChatAll("%d %d %s", Client, Money, String); Like pride95's example

Thanks again and sorry for bothering, I did it and it still made the error (number of arguments does not match definition) in the name line -

Quote:

public Action:Command_health(client, args)
{
int health = GetClientHealth(client);
int name = GetClientName(client);
PrintToChatAll("%i %N ", health, name)
}

Psyk0tik · *Last edited by Psyk0tik; 06-08-2018 at 16:06.*

PHP Code:


			
int health = GetClientHealth(client);
PrintToChatAll("%N %d", client, health);

The "%N" automatically gets the name of whatever index you use. Since you're getting the client's name, just use "client" as your index.

MasterMind420

Quote:

Originally Posted by Crasher_3637

PHP Code:


			
int health = GetClientHealth(client);

PrintToChatAll("%N %d", client, health);

The "%N" automatically gets the name of whatever index you use. Since you're getting the client's name, just use "client" as your index.

Very good point lol...I completely overlooked that