[YamiKaitou]

Originally Posted by fysiks I believe it means decimal 3 would show as binary 11 and decimal 5 would show as binary 101.

Fixed

[fysiks]

Originally Posted by YamiKaitou Fixed

Yes, but it's actually in decimal. It's the digits that are being displayed. So 5 shown as "binary" would be one hundred and one (which is a decimal number)

I'm sure the four of us understand. Just want to make it clear to those who don't.

[K.K.Lv]

Good job !

and I have problem, maybe it's a request !

In China we need to save the file with UTF-8 without bom .
so , if I want to use log function, then the char of the cn part can be read !
I poor on C++, and I have no idea in pawn !
hope you can do it !
sorry for my bad en !

[Seta00]

Originally Posted by Exolent[jNr] It's mainly for display purposes since it wouldn't necessarily be helpful in code.

Originally Posted by fysiks I believe it means decimal 3 would show as decimal 11 and decimal 5 would show as decimal 101. I wondered this before also but took me a while to figure it out lol. Seems only good for arguments of printf() like functions (as Exolent said).

I'm not stupid
My point was anything above 1023 will result in an overflow, it should write to a string as the other stocks.

[ot_207]

Originally Posted by Seta00 I'm not stupid My point was anything above 1023 will result in an overflow, it should write to a string as the other stocks.

Yup. Also a format function would be a good idea.
Ex:
extraformat("Number: %d %x %b", 5, 11, 5)
Output: Number 5 0xB 0000...0101

[jim_yang]

Originally Posted by ot_207 Yup. Also a format function would be a good idea. Ex: extraformat("Number: %d %x %b", 5, 11, 5) Output: Number 5 0xB 0000...0101

good idea, should be in the amxx core
better to be powerful as c++/cli's String::Format

[Exolent[jNr]]

Originally Posted by Seta00 I'm not stupid My point was anything above 1023 will result in an overflow, it should write to a string as the other stocks.

I knew it was going to have a limit, but I didn't take the time to see what it was.
I suppose there's no reason for having one function with a limit and another without.
I replaced the original <Number>ToBinary and BinaryTo<Number> with the string versions.

[Seta00]

Originally Posted by Exolent[jNr] I knew it was going to have a limit, but I didn't take the time to see what it was. I suppose there's no reason for having one function with a limit and another without. I replaced the original <Number>ToBinary and BinaryTo<Number> with the string versions.

cell = 32bits, limit = 2^32-1
Nice addition

[Exolent[jNr]]

Originally Posted by Seta00 cell = 32bits, limit = 2^32-1 Nice addition

I know the 32bit limit for integers, but I was talking about the 1023 limit.
I knew the binary integer result would be the decimal result of converting 1111111111 but I didn't take the time to look at it.

[Seta00]

Originally Posted by Exolent[jNr] I know the 32bit limit for integers, but I was talking about the 1023 limit.

Necroposting because of distraction (didn't see your reply):

The unsigned integer limit is 4 294 967 295, 10 characters long. 1023 = 2^10-1, 10 characters long as well. Everything above 1023 is eleven characters long or more, which means integer overflow.