[thEsp]

Hello, I want to know how can I split a string which contains " " (space), but outside quotes.
I tried a variety of functions, neither of them worked. I even tried making a stock, but don't know where the problem is.
For instance, this is a full string: "value num1" "value num2". Instead of returning "value" "num1 ..." it would return the correct way, "value num1","v...".

(Used this ->)

PHP Code:

stock string_arg_split(const string[],right[],left[],const delim[])
{
    new return_right[128]
    new return_left[128]
    new bool:in_quote
    new bool:is_right
    
    for(new i=0;i<strlen(string);i++)
    {
        if(equal(string[i],"^"")) // Code below is red, wth?
        {
            if(in_quote)
            {
                in_quote=false
            }else{
                in_quote=true
            }
        }

        if(!in_quote && equal(string[i],delim))
        {
            if(is_right)
            {
                is_right=false
            }else{
                break
            }
        }else{
            if(is_right)
            {
                add(return_right,charsmax(return_right),string[i])
            }else{
                add(return_left,charsmax(return_left),string[i])
            }
        }
    }
    set_string(2,return_right,strlen(right))
    set_string(3,return_left,strlen(left))
} 


Thank you in advance !

[EFFx]

The red code is because you need ^"^", you have only one. Also, did u try parse?

[thEsp]

Originally Posted by EFFx The red code is because you need ^"^", you have only one. Also, did u try parse?

Seems with parse() it works, thank you!

[Natsheh]

Originally Posted by EFFx The red code is because you need ^"^", you have only one.

Not really he is doing it right it's seems he is seeking for an open qoute character and he is doing it wrong he have to specified the 3rd param in equal function and set it to 1 if(equal(string[i],"^"", 1)) or he could simply check if(string[i] == '^"');