[Arkshine]

Originally Posted by Bugsy My mistake You left out a closing brace for the for-loop in both CountNumbers functions

Where?

so what sould i do?T_T

Try :

IsContainingLetters( const String[] )
{
    new Count;
    new Len = strlen( String );
    
    for ( new i = 0 ; i < Len ; i++ )
    {
        if ( isalpha( String[ i ] ) )  { return true; }
    }
    
    return false;
}

[_lol_]

thanks

[loiraolhosazul]

how would it be to accept only letters and numbers? both uppercase and lowercase letters

[Bugsy]

Use a loop to check each character in the string.

Check that the char is between 0-1, a-z, A-Z. Many ways to do this.

PHP Code:

bool:IsStringLettersAndOrNumbers( const szString[] )
{
    new bool:bStringOk = true , iLen = strlen( szString );
    
    for ( new i = 0 ; i < iLen ; i++ )
    {
        if ( !( '0' <= szString[ i ] <= '9' ) && !( 'a' <= szString[ i ] <= 'z' ) && !( 'A' <= szString[ i ] <= 'Z' ) )
        { 
             bStringOk = false;
             break;
        } 
    }
    
    return bStringOk;
} 


[loiraolhosazul]

Originally Posted by Bugsy Use a loop to check each character in the string. Check that the char is between 0-1, a-z, A-Z. Many ways to do this. PHP Code: bool:IsStringLettersAndOrNumbers( const szString[] ) {     new bool:bStringOk = true , iLen = strlen( szString );          for ( new i = 0 ; i < iLen ; i++ )     {         if ( !( '0' <= szString[ i ] <= '9' ) && !( 'a' <= szString[ i ] <= 'z' ) && !( 'A' <= szString[ i ] <= 'Z' ) )         {               bStringOk = false;              break;         }      }          return bStringOk; }

thanks