[Exolent[jNr]]

everyone knows that "=" means "equals", but does that mean i could do this:

new x, y;
x = y = 5;

then x and y would equal 5?

thats not my code exactly, but thats what im trying to accomplish is that two variables would equal the same value with 1 statement.

[Arkshine]

You can.

But why did not you tested, instead of posting here ? It takes few seconds to see by yourself...

[[kirk]./musick`]

Now x equals what y equals (5).

[_Master_]

That's not exactly how it works kirk...

Simply put the expression is valuated from right to left. "y = 5" valuates to "5". Then "x = <5>" again valuates to "5" which means that the entire expression valuates to "5".

This can be used for other purposes as well.
Ex: "if( x = y = A < 7 )" The condition will be true if A < 7.
Ex: "x = y = x - y" is identical to "y = x - y; x = y"

You can make an undefined chain of initializations like this. Just make sure those are l-values,
except for last op which can be a r-value ( ie. you can't make a statement like "x = y - 2 = 5" because "y - 2" is not a l-value )

Same rule applies here: "if( fp = fopen( ... ) )" tho the AMXX compiler will give a warning about a possible incorrect assignment.

[[kirk]./musick`]

Ah, but it still evaluates to the same value.