[Keeper]

Meaning I bet he's trying to compare the result of text[0] to a const char*.

[sn4k3]

Originally Posted by Keeper Meaning I bet he's trying to compare the result of text[0] to a const char*.

no i using yours exemples

with char *

char *sText = "Hey";
char *sFirstLetter = ( Q_strlen(sText) != 0 ? sText[0] : "" );

Or

char* s = "Hey";
char* f = (strlen(s) != 0 ? s[0] : "");

= errors in compile for me

[Keeper]

Try this then:

const char* text = "#text";
if (text[0] == '#') {
// do your code here
}

or:

char *sText = "Hey";
char sFirstLetter = ( strlen(sText) != 0 ? sText[0] : 0 );

[sn4k3]

Originally Posted by Keeper Try this then: const char* text = "#text"; if (text[0] == '#') { // do your code here } or: char *sText = "Hey"; char sFirstLetter = ( strlen(sText) != 0 ? sText[0] : 0 );

ty i gona try

i have used last exemple i think and works in compile but crash on use but i will try

[showdax]

Originally Posted by Keeper char *sText = "Hey"; char sFirstLetter = ( strlen(sText) != 0 ? sText[0] : 0 );

Don't do this. I just went over how that's all completely unnecessary!

[Keeper]

I understand what you said, but I was posting how the given example could be made to work.

using "char sFirstLetter = sText[0]" would be fine too...

[sn4k3]

Originally Posted by Keeper I understand what you said, but I was posting how the given example could be made to work. using "char sFirstLetter = sText[0]" would be fine too...

ty yours exemples works