[mabaclu]

I've sucessfully beaten OP, now you have to send me 50€ via PayPal.

[Shadows In Rain]

Okay then. Just 8 characters? I can do it with 6.
My current results:

PHP Code:

@@()@@ 


My previous (hashed) results:

PHP Code:

@@()@@()//...$a|t... 


PHP Code:

@@(){}//...$a|t... 


Why it's possible? If symbol starts with "@", symbol implicitly treated as public. Why not just "@" alone? Because "@" alone treated as operator. By the way, "@" may be used anywhere in symbol name, e.g. you can write:

PHP Code:

new const hello@world[] = "Hello, world." 


[Shadows In Rain]

Pawn stares at YOU!
@@()@@

[YamiKaitou]

Seems you violated one of your conditions...

Originally Posted by Shadows In Rain — It can do something (no matter what).

[Shadows In Rain]

Originally Posted by YamiKaitou Seems you violated one of your conditions...

If you call "@@", it will yield stack overflow.

[mabaclu]

Originally Posted by YamiKaitou Seems you violated one of your conditions...

He didn't violate because that's not even a rule. Learnt something new here, thanks for the challenge.

[.Dare Devil.]

Originally Posted by Shadows In Rain If you call "@@", it will yield stack overflow.

It never get a call...

Now my code

PHP Code:

forward pfn_think(a)
native remove_entity(iIndex)
public pfn_think(a) remove_entity(a) 


It will crash your game, still doing something...

[Shadows In Rain]

Actually I wonder how operator "@" is used. Because I can't find anything about it, even in compiler sources.

[mabaclu]

Its in Pawn's manual. It's used as you said and can also be used to create public variables.

[Shadows In Rain]

Originally Posted by mabaclu Its in Pawn's manual. It's used as you said and can also be used to create public variables.

In compiler sources it is written that "@" alone (i.e. when not attached to other characters) treated as operator (just like "+" or "-" etc).

pawn-4.0.4733/source/compiler/sc2.c, line 2125:

    if (_lexstr[0]==PUBLIC_CHAR && _lexstr[1]=='\0')
      _lextok=PUBLIC_CHAR;      /* '@' all alone is not a symbol, it is an operator */