while i++ == containi[i] problem, i need to skip letters ( fixed)

Owyn · **Author**

PHP Code:


			
new said[6], i = 0
    read_argv(1, said, 5)
    
    while (containi(said[i], "> !") != -1)
    {
        i++
    }
    
    while (said[i] == '!')
    {
        i++
    }

hi, i'm trying to modify admin chat, so when admin types !hi it will make a hud message like @hi, but also i want to make a hud message appear he admin types > !hi
and this part i can't get to work, when admin types > !hi nothing happens, it just shows in chat like usual

and i tried

PHP Code:


			
if (containi(said, "> !") != -1)
    {
        i++
        log_amx("> ! Found!")
    }

but when admin typed > !hi
nothing it didn't found it )= no amx log was made

and if i do while (containi(said[i], "!") != -1) it works only for first characters, i want to make string like "> !hi" make an hud chat like @hi and "> !!hi" make it like @@hi

fysiks · 04-10-2009 , 08:32 Re: while i++ == containi[i] problem

You are comparing a single character (said[i]) to a string of three characters ("> !")

Owyn · *Last edited by Owyn; 04-10-2009 at 08:46.*

yea i thought of it, and i want to know how make comparation right so it would compare to three characters right and after remove it from message like it removes "!" if it begins with em and make i++ or a thing like that like this code does with single character !

PHP Code:


			

    while (said[i] == '!')
    {
        i++
    }

fysiks · 04-10-2009 , 08:45 Re: while i++ == containi[i] problem

Code removed.

But, the first character after the last '!' will be expected to be a color indicator.

Owyn · 04-10-2009 , 08:51 Re: while i++ == containi[i] problem

Quote:

replace(said, "> ", "")

that gives an argument type mismatch (arg 2) error on compile

Spunky · 04-10-2009 , 08:54 Re: while i++ == containi[i] problem

Code:

replace(said, 5, "> ", "")

fysiks · 04-10-2009 , 08:54 Re: while i++ == containi[i] problem

Oops, I forgot an argument. http://www.amxmodx.org/funcwiki.php?go=func&id=47

Wow, three posts all at once

.

Owyn · 04-10-2009 , 09:02 Re: while i++ == containi[i] problem

PHP Code:


			
new said[6], i = 0
    read_argv(1, said, 5)
    
    if(contain(said, "> !") != -1)
    {
        replace(said, 5, "> ", "")
    }
    
    while (said[i] == '!')
    {
        i++
    }

does not work, it does not catch when i type "> !hi" and does nothing

fysiks · 04-10-2009 , 09:06 Re: while i++ == containi[i] problem

Quote:

Originally Posted by .Owyn.

does not work, it does not catch when i type "> !hi" and does nothing

Try to debug it then.

Owyn · 04-10-2009 , 09:07 Re: while i++ == containi[i] problem

i get no errors, and as i mentioned in 1st post thins condition does not met, dunno what is wrong