[Dragos]

Hello,

I'm pretty sure it was a function like this.

So, It check If the entered words contain only numbers, no words

PHP Code:

new szArg[192];
    read_args( szArg, charsmax( szArg ) );
    remove_quotes( szArg );
    new ids = str_to_num(szArg)
    
    if(ids == 0) {
        culoare(id, "!g[!tSYSTEM!g] !tWe Accept Only Numbers")
        return PLUGIN_HANDLED;
    } 


If I write like 123456 it block me
But If I type 123456A, it allow him and pass next

[Bugsy]

Use is_str_num()

[Natsheh]

PHP Code:


stock bStringAreNumbers(const String[])
{
   for(new i, maxloop = strlen(String); i < maxloop; i++)
   {
      if( ! ( '0' <= String[ i ] <= '9' ) ) return false;
   }
   return true;
} 


although listen for what bugsy told you, this example is just for clarification!

[Dragos]

My bad, I wanted to say that If I type 123456 [Need to type regular numbers to pass] it let me go, but If I type 123456A it still pass me <-- [And this is what I want to block] [What I want to block it's that , If I type some numbers and in that numbers contain a words is should return ]

[Dragos]

It lock like doing it negative it solved my problem

PHP Code:

if(!bStringAreNumbers(szArg)) {
        culoare(id, "!g[!tSYSTEM!g] !tWe Accept Only Numbers");
        return PLUGIN_HANDLED;
    } 


Ty

[loiraolhosazul]

Or:

PHP Code:

stock bool:xValidNumber(const xStr[])
{
    new const xNumbers[][] =
    {
        "0", "1", "2", "3", "4", "5", "6", "7", "8", "9"
    }
    
    new xLen = strlen(xStr)
    new i, a, xValids
    
    for(i = 0; i < xLen; i++)
    {
        for(a = 0; a < sizeof(xNumbers); a++)
        {
            if(xStr[i] == xNumbers[a][0])
            {
                xValids ++
                break
            }
        }
    }
    
    if (xValids != xLen)
        return false
    
    return true
} 


[Bugsy]

Beating this one to death guys..I'd just use the native is_str_num() and call it a day. Natsheh's function is better/more efficient than what you posted, loiraolhosazul.