[Solved] Amxx 1.8.3 - random()

CrazY. · **Author**

Hello, I find a bug in the random() native. It's returning a completely absurd number, about 50000 times bigger!

PRoSToTeM@ · 12-15-2017 , 13:33 Re: Amxx 1.8.3 - random()

Code to reproduce?

CrazY. · 12-15-2017 , 13:42 Re: Amxx 1.8.3 - random()

Code:

new Array:g_hArraySounds = ArrayCreate(64, 1);

Code:

ArrayGetString(g_hArraySounds, random(ArraySize(g_hArraySounds) - 1), szSound, charsmax(szSound));

OciXCrom · 12-15-2017 , 13:50 Re: Amxx 1.8.3 - random()

And what does this return? Better provide a full working code. Also, -1 is not needed here unless you want to ignore the last array entry on purpose.

CrazY. · 12-15-2017 , 14:09 Re: Amxx 1.8.3 - random()

My bad, the problem was in the -1 that I added.

OciXCrom · 12-15-2017 , 14:44 Re: Amxx 1.8.3 - random()

I don't see how that could be the problem. The -1 just made it ignore the last array entry when choosing a random one.

CrazY. · 12-15-2017 , 15:31 Re: Amxx 1.8.3 - random()

It's because there was only 1 item stored in the array.

OciXCrom · 12-15-2017 , 16:21 Re: Amxx 1.8.3 - random()

Ah, I see.