[stickz]

I created an sm_botpow command to output how many bots my exponential equations add.

It currently produces the following output. The base is sometimes multiplied by 100 after calculation.

] sm_botpow
--> Physical Player Difference <--
Round: 1 ^ 2.15 = 1
Round: 2 ^ 2.15 = 4
Round: 3 ^ 2.15 = 11
Round: 4 ^ 2.15 = 20
Round: 5 ^ 2.15 = 32

--> Low Uneven Skill Percent Difference <--
Round: 100 ^ 1.75 = 1
Round: 200 ^ 1.75 = 3
Round: 300 ^ 1.75 = 7
Round: 400 ^ 1.75 = 11
Round: 500 ^ 1.75 = 17

--> High Uneven Skill Percent Difference <--
Round: 100 ^ 1.89 = 1
Round: 200 ^ 1.89 = 4
Round: 300 ^ 1.89 = 8
Round: 400 ^ 1.89 = 14
Round: 500 ^ 1.89 = 21

--> Even Skill Percent Difference <--
Round: 150 ^ 1.39 = 2
Round: 200 ^ 1.39 = 3
Round: 250 ^ 1.39 = 4
Round: 300 ^ 1.39 = 5
Round: 350 ^ 1.39 = 6

For the bottom three i'm trying to solve the following equation: b ^ 1.89 = 5. Any help would be greatly apperated. I can't figure out how to use the logarithm function.

[eyal282]

b = 1.89root(5)

Not square root, but root of base 1.89.
5 ^ x = 9 --> x = Logarithm(9, 5)
x ^ 5 = 9 --> x = Pow(9, 1/5)

Quickly check I'm not wrong. The 1 / 5 simulates base root

[stickz]

I have the following code now.

void WriteConsoleSkillValues(int client, float mult)
{
	for (int base = 1; base <= 10; base++)
	{
		float value = Pow(float(base), 1.0 / mult) * 100.0;
		PrintToConsole(client, "Round: %d% ^ %.2f = %d", RoundToNearest(value), mult, base);
	}
}

Which produces the following output.

--> Low Uneven Skill Percent Difference <--
Round: 100 ^ 1.75 = 1
Round: 149 ^ 1.75 = 2
Round: 187 ^ 1.75 = 3
Round: 221 ^ 1.75 = 4
Round: 251 ^ 1.75 = 5
Round: 278 ^ 1.75 = 6
Round: 304 ^ 1.75 = 7
Round: 328 ^ 1.75 = 8
Round: 351 ^ 1.75 = 9
Round: 373 ^ 1.75 = 10

--> High Uneven Skill Percent Difference <--
Round: 100 ^ 1.89 = 1
Round: 144 ^ 1.89 = 2
Round: 178 ^ 1.89 = 3
Round: 207 ^ 1.89 = 4
Round: 233 ^ 1.89 = 5
Round: 257 ^ 1.89 = 6
Round: 278 ^ 1.89 = 7
Round: 299 ^ 1.89 = 8
Round: 318 ^ 1.89 = 9
Round: 336 ^ 1.89 = 10

--> Even Skill Percent Difference <--
Round: 100 ^ 1.39 = 1
Round: 164 ^ 1.39 = 2
Round: 219 ^ 1.39 = 3
Round: 269 ^ 1.39 = 4
Round: 316 ^ 1.39 = 5
Round: 360 ^ 1.39 = 6
Round: 401 ^ 1.39 = 7
Round: 442 ^ 1.39 = 8
Round: 480 ^ 1.39 = 9
Round: 518 ^ 1.39 = 10

My code is rounding to ceiling instead to nearest like I want. Is there any way I can resolve this issue and calculate the nearest value instead?

[eyal282]

Originally Posted by stickz I have the following code now. void WriteConsoleSkillValues(int client, float mult) { for (int base = 1; base <= 10; base++) { float value = Pow(float(base), 1.0 / mult) * 100.0; PrintToConsole(client, "Round: %d% ^ %.2f = %d", RoundToNearest(value), mult, base); } } Which produces the following output. --> Low Uneven Skill Percent Difference <-- Round: 100 ^ 1.75 = 1 Round: 149 ^ 1.75 = 2 Round: 187 ^ 1.75 = 3 Round: 221 ^ 1.75 = 4 Round: 251 ^ 1.75 = 5 Round: 278 ^ 1.75 = 6 Round: 304 ^ 1.75 = 7 Round: 328 ^ 1.75 = 8 Round: 351 ^ 1.75 = 9 Round: 373 ^ 1.75 = 10 --> High Uneven Skill Percent Difference <-- Round: 100 ^ 1.89 = 1 Round: 144 ^ 1.89 = 2 Round: 178 ^ 1.89 = 3 Round: 207 ^ 1.89 = 4 Round: 233 ^ 1.89 = 5 Round: 257 ^ 1.89 = 6 Round: 278 ^ 1.89 = 7 Round: 299 ^ 1.89 = 8 Round: 318 ^ 1.89 = 9 Round: 336 ^ 1.89 = 10 --> Even Skill Percent Difference <-- Round: 100 ^ 1.39 = 1 Round: 164 ^ 1.39 = 2 Round: 219 ^ 1.39 = 3 Round: 269 ^ 1.39 = 4 Round: 316 ^ 1.39 = 5 Round: 360 ^ 1.39 = 6 Round: 401 ^ 1.39 = 7 Round: 442 ^ 1.39 = 8 Round: 480 ^ 1.39 = 9 Round: 518 ^ 1.39 = 10 However, it's not precise enough. Is there any way I can make this more precise? The equation is evaluating as if 1.39 and 1.89 are sent, but the values actually being sent are 1.40 and 1.90.

Maybe use %.2f instead of %d ( you don't round %.2f ) but I know that floats cannot represent exact values.

[stickz]

The issue I have is 1.64 ^ 1.39 almost precisely equals 2. This not entirely the behavior I want.

I'm trying to calculate the base using IEEE rounding standards, that would round upwards to 2.

For instance 1.35 ^ 1.39 would equal 1.5176 which would round upwards to 2 using IEEE standards.

I think a logarithm is required for this behavior. I can't just raise the value to 1 / exponent.

[eyal282]

Originally Posted by stickz The issue I have is 1.64 ^ 1.39 almost precisely equals 2. This not entirely the behavior I want. I'm trying to calculate the base using IEEE rounding standards, that would round upwards to 2. For instance 1.35 ^ 1.39 would equal 1.5176 which would round upwards to 2 using IEEE standards. I think a logarithm is required for this behavior. I can't just raise the value to 1 / exponent.

I don't 100% follow you but not rounding appears to be what you're trying to do. Instead of rounding 1.5176 to 2, keep it 1.5176.

[Fyren]

Which specific operation are you claiming is wrong?

The output you gave us not helpful because it doesn't show the true value of mult, so we can't really verify anything. From only the code you gave and the output it produced, it doesn't look like anything is wrong. (You're also printing like "373 ^ 1.75 = 10" but obviously you're not doing 373 ^ 1.75, so that's not helping you try to explain anything.)