[Bugsy]

Originally Posted by drekes and if i make normal array like your example here PHP Code: new TheArray[] = "hello"; //size = 6, 5 chars + 1 null  and i want to change the "hello" to "bye" which is 1 character shorter than hello, i still don't have to define it when i created it? and i want to check the y i do PHP Code: if(ACH[1] == y)

You can do this two ways.

Using a function (copy\formatex\etc):

PHP Code:

new TheArray[] = "hello";

copy( TheArray , charsmax( TheArray ) , "bye" ); 


Or manually:

PHP Code:

new TheArray[] = "hello";

TheArray[ 0 ] = 'b';
TheArray[ 1 ] = 'y';
TheArray[ 2 ] = 'e';
TheArray[ 3 ] = EOS; 


Just keep in mind, you cannot store more than 5 characters in TheArray since it is declared holding 'hello' which limits it to 5 characters as a string or a 6 number array.

[drekes]

Okay, now i'm sure i found the point again.
Thanks guys

About the 2 characters: I'm really not that good in counting stuff, it's because of the double "L" i missed it.

EDIT: i'm not completly sure, but regarding to your earlier post, i guess "EOS" is a null character, right?

[wrecked_]

@Bugsy - Even though I probably won't ever be using this, is EOS really the null terminator for a string?

[Bugsy]

Originally Posted by wrecked_ @Bugsy - Even though I probably won't ever be using this, is EOS really the null terminator for a string?

Yes.

Pawn language guide:

EOS: predefined constant standing for End Of String; it has the value ’\0’

[wrecked_]

Originally Posted by Bugsy Yes. Pawn language guide: EOS: predefined constant standing for End Of String; it has the value ’\0’

Ah, yeah. I got confused because I was familiar with \0 being the common null terminator.

[drekes]

Thanks.