[Natsheh]

Originally Posted by fysiks See Two's Complement.

Thanks I understood the technique but I've heard once they define the negative numbers by setting the last bit to 1 is that even correct?

Originally Posted by Bugsy Read up on bits, there are tutorials all over the net, they are not specific to AMX-X. What didn't work in the code I posted? It worked for me PHP Code: public test()  {     new iVal = ~0;     new szBits[ 40 ];     new iStringPos = charsmax( szBits );          szBits[ iStringPos ] = EOS;          for ( new i = 31 ; i >= 0 ; i-- )     {         szBits[ charsmax( szBits ) - iStringPos-- ] = iVal & ( 1 << i ) ? '1' : '0';                  if ( !( iStringPos % 5 ) && ( iStringPos > 0 ) )             szBits[ charsmax( szBits ) - iStringPos-- ] = ' ';         }          server_print( "Value = %d" , iVal );     server_print( "Bits = %s" , szBits ); }  Output: Value = -1 Bits = 1111 1111 1111 1111 1111 1111 1111 1111

What compiler did you use for the test?

[Bugsy]

I am currently on a relatively old 1.9 build

[Natsheh]

Originally Posted by Bugsy I am currently on a relatively old 1.9 build

YUP it works fine for some reason when i tested it was bugging because some other bug thats why

[fysiks]

Originally Posted by Natsheh Thanks I understood the technique but I've heard once they define the negative numbers by setting the last bit to 1 is that even correct?

With two's complement, the most-significant (left most) bit does happen to be a 1 but you can't change the sign of a number by just changing that bit.