[EFFx]

It is not used because instead of

PHP Code:

if(!!g_admin[id]) 


is just

PHP Code:

 if(g_admin[id]) 


Right?

Then with that the !! is useless.

Edit:

Originally Posted by fysiks Using this on a boolean makes absolutely no sense since it's a double negative and will always return the original value.

That's what I understood.

[fysiks]

Originally Posted by EFFx It is not used because instead of PHP Code: if(!!g_admin[id])  is just PHP Code:  if(g_admin[id])  Right? Then with that the !! is useless.

Like I said before, it depends on what g_admin[id] contains. If it contains booleans then you use it as a boolean.

If you use an integer in an if statement, it would be equivalent to variable != 0 or !!variable.

[EFFx]

Yes dude. As said before as well, it was an example.

Or just !variable

Why would I convert an interger to a boolean ? In what kinda function? Just add bool tag.

[PRoSToTeM@]

Sometimes you need to check if both conditions are true or false (have the same bool value), like both players are alive or dead. If you will work with ints it will be failed, because, for example first condition has 7 and second condition has 2, 7 == 2 fails, but (7 != 0) == (2 != 0) is ok.

[fysiks]

Originally Posted by EFFx Yes dude. As said before as well, it was an example. Or just !variable Why would I convert an interger to a boolean ? In what kinda function? Just add bool tag.

Since it is hard for you to understand how this works, you can simply just never use it and you will be just fine. It is not a necessary operator since there are other ways to do it (like comparing to zero).

[Kotoamatsukami]

Originally Posted by KliPPy It's not a single operator, but negation operator "!" being done twice. You would want to use that when you want to coerce a cell into a boolean, following the rule that 0 = false, anything else = true. !!(0) == false !!(1) == true !!(42) == true !!(-69) == true This way you are making sure that your boolean is either "true" or "false" and not bool:420 for example. That's good because some people prefer to do "if(variable == true)" instead of "if(variable)", which won't give correct results if you don't "normalize" your boolean value.

Pardon me.
Based on your explanation, what I understand is;

PHP Code:

new i_Variable = 0

if( !!i_Variable ) 


That will not let the 'if' statement functional, right? So if we do;

PHP Code:

new i_Variable = 1

if( !!i_Variable ) 


Then, this will make the 'if' statement functional. Well, it is not all time should be storing '1' even other than '1' is still available, as long as the variable did not store '0'.

Correct me if I am wrong.
Thank you.

[kristi]

PHP Code:


if(0) // false

if(1) // true

if(2) // false

if(!!2) // true 


Is this right ?

[PRoSToTeM@]

No, if (2) is true as if (!!2) and if (2 != 0).

PHP Code:

new x;
...
x; // integer (_) with value of x
bool:x; // bool with value of x
!!x; // bool with true if x != 0 and false if x == 0
x != 0; // the same as !!x 


PHP Code:

new x, y;
...
// These are identical
if (x)
if (x != 0)
if (!!x)

if (x == y) // true if x = y
if (!!x == !!y) // x and y both are not zero or both are zero
if ((x != 0) == (y != 0)) // same as the previous
if (!x == !y) // also same