#pragma semicolon 1

r3D w0LF · **Author**

By default semicolons are not needed, and new line means "new start".
Now, im not sure how it works on pawn as I havent really played much, but im guessing:

Code:

myFunc()
myFunc2()

should run fine (returning whatever it should),
Lets say that I force semicolons, the above wont work unless I add a semicolon. But will this work:

Code:

myFunc(); myFunc2();

? Or do they need to be in a different line in order to work?

JusTGo · 03-11-2018 , 14:57 Re: #pragma semicolon 1

best way to know that is by compiling the script.

klippy · 03-11-2018 , 15:01 Re: #pragma semicolon 1

Why don't you try it? If the compiler complains then it doesn't work. As far as I know that will work.

hellmonja · 03-12-2018 , 09:20 Re: #pragma semicolon 1

Works every time for me...

PHP Code:


			
static bpammo; bpammo = cs_get_user_bpammo(id, CSW_NEWPN);

r3D w0LF · 03-12-2018 , 09:57 Re: #pragma semicolon 1

Yeah, why not, I actually tried myFunc(); myFunc2() without forcing semicolons and it worked, so im supposing that forcing semicolons wouldnt be a difference, thanks

fysiks · 03-12-2018 , 21:40 Re: #pragma semicolon 1

By requiring semicolons, it merely requires them at the end of all statements. Not requiring them doesn't make them not work, you can still use them like normal.