[Flipper_SPb]

How to count ^n symbols in the string?

[Exolent[jNr]]

stock str_count(const haystack[], const needle[], ignorecase=0)
{
    new c
    new old, pos, len = strlen(needle)
    while((pos += (ignorecase ? containi(haystack[old], needle) : contain(haystack[old], needle))) >= old)
    {
        c++
        old = pos + len
    }
    return c
}

new count = str_count(string, "^n")

[Flipper_SPb]

Thank you, Exolent

[xPaw]

Here's same but for character counting, without natives inside loop.

stock char_count( const hayshack[ ], const needle )
{
    new iCount, i, iLen = strlen( hayshack );
    
    while( i++ < iLen )
    {
        if( hayshack[ i ] == needle )
        {
            iCount++;
        }
    }
    
    return iCount;
}

new count = char_count( string, '^n' );

[Exolent[jNr]]

Originally Posted by xPaw without natives inside loop. iLen = strlen( hayshack );

Liar.

EDIT:

I would do this:

stock char_count( const hayshack[ ], const needle )
{
    new iCount, i = -1, iChar;
    
    while( ( iChar = hayshack[ ++i ] ) )
    {
        if( iChar == needle )
        {
            iCount++;
        }
    }
    
    return iCount;
}

[Flipper_SPb]

I made that:

PHP Code:

new i, c, count_n

while((c = my_string[i++]))
        count_n += _:(c == 10) 


[xPaw]

Originally Posted by Exolent[jNr] Liar.

I said INSIDE loop ;)
Both ways are fine.