[0920357689]

PHP Code:

...
{
    new num[5]
    get_num(num)
}
stock / public? get_num(?)
{
    for(new i=0; i<5; I++)
        num = i;
    ...?
} 


how to return array?

[Liverwiz]

public getArray(iNum, output[])
{
    for(new i = 0; i < sizeof output; i++)
        output[i] = --iNum
}

will return an arrray. You have to put it in the paramaters, and it will be passed as a pointer.

[0920357689]

Originally Posted by Liverwiz public getArray(iNum, output[]) { for(new i = 0; i < sizeof output; i++) output[i] = --iNum } will return an arrray. You have to put it in the paramaters, and it will be passed as a pointer.

not work

PHP Code:

new Num, ABC = Get_Num(Num)
client_print_color(0, TextColor, "%d", ABC);

public Get_Num(Num)
{
    Num= 99;
} 


the num show "0"

[YamiKaitou]

Num is not an array. If you want to do that, you must use
public Get_Num(&Num)

[0920357689]

Originally Posted by YamiKaitou Num is not an array. If you want to do that, you must use public Get_Num(&Num)

i know is not array.....

add & not work too....why?
still show "0"


and use #2 core show
indeterminate array size in "sizeof" expression (symbol "")
send array work. but can't send num...

[0920357689]

sorry....is my core Problem
now is work...thx for help

[fysiks]

Originally Posted by 0920357689 i know is not array..... add & not work too....why? still show "0" and use #2 core show indeterminate array size in "sizeof" expression (symbol "") send array work. but can't send num...

Because you don't return anything (which will default to 0). You have to do one of the following:

new iValue;
GetNum(iValue);
// iValue will be 99

stock GetNum(&iNum)
{
	iNum = 99;
}

or

new iValue;
iValue = GetNum();
// iValue will be 99

stock GetNum()
{
	return 99;
}

[0920357689]

Originally Posted by fysiks Because you don't return anything (which will default to 0). You have to do one of the following: new iValue; GetNum(iValue); // iValue will be 99 stock GetNum(&iNum) { iNum = 99; } or new iValue; iValue = GetNum(); // iValue will be 99 stock GetNum() { return 99; }

no my core is
num + array

PHP Code:

public Get_Num(&num, num_array[]) 


now work

[fysiks]

Well it's nice of you to not explain anything correctly and expect help.

My post is still accurate.