[pepe_thugs]

Hello Guys.
Is there any way to remove all the characters following the other characters?

Example:

pepethugs lalalalalal

After Remove:

pepethugs

Remove the characters "lalalalalal"

[Black Rose]

Is it supposed to strip everything after a space or is it supposed to strip everything behind that specific phrase "pepethugs"?

[pepe_thugs]

Originally Posted by Black Rose Is it supposed to strip everything after a space or is it supposed to strip everything behind that specific phrase "pepethugs"?

Is to strip after one character. I have this:

Pepethugs <1234><A>

And i want to strip all after pepethugs or strip after "<" Including the character "<"

[HamletEagle]

To remove everything after "<", including it, you can do:

PHP Code:

new Pos
if((Pos = contain(String, "<")) != -1)
{
    String[Pos] = EOS
} 


[Bugsy]

PHP Code:

new Pos
if((Pos = contain(String, "<")) != -1)
{
    String[Pos] = EOS
} 


You left a redundant contain(String, "<") in the code

[pepe_thugs]

Thanks HamletEagle.
I will test it tomorow.

#Bugsy
How you suggest?
thanks

[fysiks]

Originally Posted by HamletEagle To remove everything after "<", including it, you can do: PHP Code: new Pos if((Pos = contain(String, "<")) != -1) {     String[Pos] = EOS }

Because I know the context here, there is major flaw in this code. If the name contains "<", it will get the wrong one.

@PepeThugs, to avoid an XY Problem, you should always provide the context in which your question is based. This will prevent people making unnecessary mistakes while trying to help you. To help provide this context, it's best if you can post the original code and maybe some of the threads that helped develop that code (if you know where it came from).

I think I found all the original threads: My original function, Original discussion with Pepe_Thugs

You will still need to explain what exactly you want changed (basically the PM you sent to me).

[Bugsy]

Originally Posted by pepe_thugs #Bugsy How you suggest? thanks

I was just pointing out that HamletEagle had a duplicate piece of code that was not needed.

As fysiks is saying, if the users name contains the '<' character, the string will be cut off there.

For example:

Suppose you were given "Bug<sy <lol123>", you would end up with "bug" instead of "bug<sy " with what HamletEagle posted. If you give more details for what you are trying to do, we can give a better method to accomplish it.

[claudiuhks]

This is how you can replace from '<' to '>'.
I hope this can help you achieve what you want.

PHP Code:

#define MAX_POS 2048

FindCharsInString(const String[], const Char1, const Char2, Pos[MAX_POS])
{
  new Total = 0;

  for (new Iter = 0; Iter < strlen(String); Iter++)
  {
    if (String[Iter] == Char1 || String[Iter] == Char2)
       Pos[Total++] = Iter;
  }

  Pos[Total] = 0;

  return Total;
}

{
   static Pos[MAX_POS], Total = 0;

   // Ensure that between <> there is no other < or >.
   // But you can also find a way out to escape these ones.
   //
   new String[128] = "Hattrick <Terrorist><Zombie><Alive>";

   Total = FindCharsInString(String, '<', '>', Pos, Total);
   // You can then replace in String from Pos[0]+1 to Pos[1]-1, from Pos[2]+1 to Pos[3]-1 and so on...
} 


[pepe_thugs]

#fysiks

You are wrong fysiks.
Because I'm not using your function.
When I asked you for help was because I was still using your function but not I now use it.
I now use another method.

PHP Code:

public ChangeTagA(id) {
    if ( !( 1 <= id <= gMaxPlayers ) || !get_pcvar_num(cvar_TeamTag) )
        return;
        
    new pname[65]
    new newname[70]
    
    pname = g_szName[id]
    //get_user_name(id, pname, 64)        
    pname = RemoveOldTag(pname, strlen(pname))
    //pname = RemoveOldPoints(pname, strlen(pname))
    
    if(g_loaded[id])
    {
            formatex(newname, 69, "%L %s <%d>", LANG_PLAYER, "TEAM_A", pname, StaticPoints[id])
            set_user_info(id, "name", newname)
    }
}

public RemoveOldTag(pname[65], p_len) {
    
    if ( ( containi(pname, "a.") != -1 || containi(pname, "b.") != -1 ) )
    {
        new newName[64], indicator
        new pos = containi(pname, "a.")
        
        if ( pos == -1 )
            pos = containi(pname, "b.")
            
        for ( new i = pos+3 ; i < p_len ; i++ )
            newName[indicator++] = pname[i]
            
        trim(newName)
        formatex(pname, charsmax(pname), "%s", newName)
        return pname
    }    
    return pname
} 


This code is the plugin made by p1mp.
For this code gets in the tag name "a." and "b."
But I'm getting into the name points forward was why we wanted to remove everything that is in front of the name because in the next match the name also contains the points and I wanted to remove them.
I also wanted to remove "<A>" I am put in the name of admins