[joaquimandrade]

Originally Posted by arkshine To avoid to use replace() ; using szWeapon[7] directly should work. [edit] Arg, it will give an error "Array must be indexed" for the #2. Not good. Though, using szWeapon[0] to get should work, but not sure if it's a good idea.

In this case it would be

format(szWeapon,13,szWeapon[7]);

I had never saw this. (returning an array pointer) (i guess it's how this is called)

[ConnorMcLeod]

Originally Posted by joaquimandrade I had never saw this. (returning an array pointer) (i guess it's how this is called)

Calling array size must match the returned array.

[joaquimandrade]

Originally Posted by ConnorMcLeod Calling array size must match the returned array.

I tried it and it can be bigger.

[Styles]

ya, this is a simple stock haha, but useful, I have something like this laying around or did at one pint..

[Lee]

Originally Posted by joaquimandrade In this case it would be: format(szWeapon,13,szWeapon[7]);

Calling a native such as format eliminates the purpose of using string slicing instead of replace().

[joaquimandrade]

Originally Posted by Lee Calling a native such as format eliminates the purpose of using string slicing instead of replace().

Replace searches, format don't. So it would be less expensive.

In this case the best way would be:

PHP Code:

public get_user_weapon2( id ) 
{
    new szWeapon[20];
    get_weaponname(get_user_weapon(id), szWeapon, charsmax(szWeapon));
    return szWeapon[7];
} 


But i didn't know that

PHP Code:

return szWeapon[7]; 


was possible

[SnoW]

So, if I understood right:

PHP Code:

func() {
    new s[5];
    s[0] = 'h';
    s[1] = 'e';
    s[2] = 'l';
    s[3] = 'l';
    s[4] = 'o';
    return s[1];
} 


would return "ello". So the question is, what would return the second char then, like 'e'?

[Lee]

The syntax for both is the same; it depends on whether the function to which you pass func() as a parameter expects a value or a reference to an array.

console_print("%c %s", func(), func());

This would, I believe, output "e ello".

if(func() == 101)
    console_print("My name is Vinny.");

This should also output the string "My name is Vinny.", because 'e' (encoded in ASCII) is equal to 101.

In your example however you would need to declare s with six cells and assign s[5] to '\0'.

[SnoW]

Thank you.

[AussenSeiter]

client_print( id, print_chat, "* Your weapon is %s!", get_user_weapon2(id) );  

If weapon is tmp/m4a1 or something it shows only the first letter why?
Example:
M4a1 = Weapon: m
tmp = Weapon: t
smokegrenade = weapon: s

EXIT: Fixed !